Question

is there a way to enter a function into wolfram that contains a constant variable

Answer 1

Use a for the constant. By the way a constant variable is a contradiction of terms.

Answer 2

Define it explicitly. For example: f(x,y)=3x+2y+c.

Answer 3

no it is not,
my variable is constant for the integration
and varies in a sum of the intergrals

Answer 4

The variable is treated* as a constant.

Answer 5

do you know how to define integers ie {1,2,3...} in wolfram

Answer 6

If you just want to integrate with respect to some variable, try putting a "d#" at the end of the expression, where # is your variable. For example: integrate (3x^2+2y)dx

Answer 7

all i am trying to do is find a result for
\[a_n ={1 \over π} \int_{-π}^π|sin(x)|cos(nx)dx\]
where n is integers

Answer 8

positive integers