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differentiate logx3^x
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is this \[\log_x(3^x)\]??
yes
i hope not because how in the world are you going to differentiate \[\log_x\]?
\[\log_x(3^x)=\frac{\ln(3^x)}{\ln(x)}=\frac{x \ln(3)}{\ln(x)}\]
oh maybe we can try this \[\log_x(3^x)=x\log_x(3)=\frac{x\ln(3)}{\ln(x)}\]
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lol
what myininaya said!
\[\ln(3) \cdot \frac{d}{dx} (\frac{x}{\ln(x)})\]
use quotient rule
zactly
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\[\ln(3) \cdot \frac{(x)' \ln(x)-x \cdot (\ln(x))'}{(\ln(x))^2}\]
get \[\frac{\ln(x)-1}{\ln^2(x)}\]
don't forget you constant multiply ln(3)
multiply the result by \[\ln(3)\]
i was getting there...
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no! :)
goodnight guys
ok you are faster g'night!
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