EXPRESS EACH PRODUCT IN SIMPLEST STANDARD FORM (g-3) (2g^2+3g+3) show steps and explain me how to do this teach me how to do these types of problems I'm a bit puzzled from winter break?
what's this?
Do you need help expanding out the brackets?
like I have problems subtracting polynomials
Okay what did you get when you multiplied everything out?
hold on a second I'm doing mission impossible two questions at the same time :(
(g-3)(2g ^{2}+3g+3) \[2g ^{3}+3g ^{2}+ 3g-6g ^{2}-9g ^{2}-9\] Make sure to collect like terms \[2g ^{3}-3g ^{2}-6g -9\]
thank you so much roger roger remember to combine like terms gotcha I will memorized for my upcoming test:D this Thursday
which question? this one?
ya :D
Explain this questions to me
ok, here's the idea (g-3)(2g ^2+3g+3) first distribute the g to everything in parentheses then distribute the -3 to everything in parentheses. then add it together. wanna try?
so we used the distributive property?
are you a visual learner pokemon?
right, we distribute each term on the left to each term on the right then we add them together
yes you use the distributing
so I got 2g63+3g^2+3g when distributive the g
good, I assume the 6 is a typo... what about the -3 ?
2g^3+3g^2+3g
right... continue.
-6g^2-9g-9
good! now add them together.
2g^3+-4g^2-6g-9
That's a little confusing, you have a few typos. seems very close though write out the step before: 2g^3+3g^2+3g -6g^2-9g-9=???
Its says to be written in standard from from highest degree to lowest (2g^3+3g^2+3g)+(-6g^2-9g-9)
yes, but you still need to simplify though...
Hey pokemon, this is how I learnt to expand. It's exactly the same as FOIL instead I use bunnies. It makes sure you don't leave any terms out. I hope it helps.
that's pretty good zed
LOL bunny that kind of cute :D
now I see my mistake I subtracted wrong
instead of 4g^2 it should be -3g^2 because -6g^2+3g^2=3g^2
so the final answer is 2g^3-3g^2-6g-9
nice! you got it! you forgot the negative sign in the post before it, but you fixed it in the answer.
thanks zed and turingtest :D
Always a pleasure pokemon :D
ok i got two more :D
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is that\[\frac{1}{x-7}\]???
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