how do i fine the slope of a line? i dont understand this.

Question

anonymous · Answer

it is y/x

anonymous · Answer

to find the slope at x=x0, use f'(x0)

anonymous · Answer

yifan, thats incorrect the formula for slope is m=y1-y2/x1-x2

anonymous · Answer

$$m=\frac{y_2-y_1}{x_2-x_1}$$

Sub in two points to find the gradient/slope.

anonymous · Answer

Slope (gradient) is the 'change in y-direction' over 'change in x-direction' between two points.
$$y _{2} - y_{1} \over x_{2} - x_{1}$$

e.g. If you have points (a, b) and (c, d)
the slope would be $$d-b \over c-a$$

anonymous · Answer

@davidzworld i mean dy/dx

anonymous · Answer

hey will  or anyone els? can you gimme an exmaple of finding the slope of a line with numbers (coordinate points) and show me the answer

anonymous · Answer

Find the equation of the line which passes through (2,4) and (4,10).

anonymous · Answer

$$x_{1} = 2, y_{1} = 4, x_{2} = 4, y_{2} = 10$$

anonymous · Answer

stil dont understand it, find me the slope of (2,5) (3,6) then, ill try to figure out how u get it.

anonymous · Answer

(6-5)/(3-2)=1

anonymous · Answer

oh ic now, so m=1 rite?

anonymous · Answer

yup that's right!
and for the other one,
Just use the equation same equation.. all you need to do is $$y2 - y1 \over x2 - x1$$=$$10-4 \over 4-2$$=$$6 \over 2$$= 3

anonymous · Answer

do this one, need help wat if the numbers are negetive like -5,-8    -8,1 how do u do it then?

anonymous · Answer

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anonymous · Answer

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anonymous · Answer

Same way, just make sure you take the negatives into account...|dw:1325681156496:dw|

anonymous · Answer

show normal e.g. plz

anonymous · Answer

so...
x1 = -5 , y1 = -8, x2 = -8, y2 = 1

$$1-(-8) \over (-8) -(-5)$$which becomes: $$1+8 \over 5-8$$ equalling:$$9 \over -3$$simplified as: $$-3$$

anonymous · Answer

The concept of slopes basically adresses how "fast" a line progresses through the y,x plane, since a line is uniform in its "growth", take any two points and measure the ratio of the growth of y against the growth of x

anonymous · Answer

Just for the record, Yifan12879 isn't incorrect. He's talking about a calculus approach using differentiation to determine the slope of a tangeant at a particular point, but I think that's a bit beyond the scope of this question (although there was no way of knowing).