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If you pour 100 grams of water from an 8 ounce can into a 16 ounce glass, by what amount does the density of the fluid change?
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It wouldn't change it would still be the same old density of 1 g/cm^3
We know: \[D=\frac{m}{V}\] If V increased by a factor of two, meaning: \[V=2V_0\] That means: \[D=\frac{m}{2V_0}\] Therefore the density is halved.
I agree you did your math right. However, if you have a 100g of water we know we have a 100ml of water. So if we are holding that 100 ml of water from a can that holds 8 oz to a can that 12 oz of water. We still only have 100 ml of water now it's just in a bigger can. we know 100ml of water= 100g of water, and we know 1 ml of water is equal to 1cm3 of water. so we are still left with 1 gram/cm3
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