Question

I need help How can I find the X and y value from the equation? (x - 10^2)+(y-10^2) = 4^2, where (10,10) center of the circle and radius 4.

Answer 1

I don't think you have the equations quite right
should be
(x - 10)^2+(y-10)^2 = 4^2

Answer 2

yes

Answer 3

i type it wrong

Answer 4

let't do a simple case

u^2+v^2=16

solve for y
v^2= 16-u^2

\[v=\pm\sqrt{16-u^2}\]

Answer 5

u=(x-10)

v=y-10

\[(y-10)=\pm\sqrt{16-(x-10)^2}\]

\[(y)=\pm\sqrt{16-(x-10)^2}+10\]

Answer 6

Ok

Answer 7

that's what you needed right?

Answer 8

actually I need to find a point (X,Y) above the circle

Answer 9

I think I need to use iteration for x value to find y