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Question about permutations.
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Prove that: \[sgn(\sigma)=sgn(\sigma^{-1})\forall \sigma \in S_n\]
what's \(S_n\)?
\[ 1 = sgn(e) \ \ \ \ \ \ \ \ \ \ \ \ \ \hbox{ where e is the identity permutation} \] \[ = sgn(\sigma \sigma^{-1}) \] \[ = sgn(\sigma).sgn(\sigma^{-1}) \] And now you have it.
Indeed! I figured it was a simple one but I wanted to post something xD
who can answer my question? or it's too hard?
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oh, S_n is the group of permutation on n objects.
are you speaking about same permutation as in combinatorics \[nPk=\frac{n!}{(n-k)!}\] because I hardly understand it here
The symmetric group right?
Yes
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