#include int main() { int counter =1; do{ printf("%d ", counter); } while(++counter

Question

#include <stdio.h>

int main()
{
int counter =1;

do{
printf("%d ", counter);
}
while(++counter <= 10);

return 0;
}

Question:
if ++counter <=10 , the 
output is 1 2 3 4 5 6 7 8 9 10.
but counter++ <=10. the
output is 1 2 3 4 5 6 7 8 9 10 11.
why counter++, the ouput 11 is included?

anonymous · Answer

First, you need to understand that the do-while structure does the checking at the end of the loop, rather than at the beginning (different than both for and while structures).
Second, whenever you do ++counter <= 10, first the program will add one and then it will check the statement <= 10 for a truth value.
So, on the second to last pass, this is more or less what happens: counter = 10 from the previous loop. do -> printf("%d ", counter) will output 10, then it goes and ++counter, counter = 11 now, is 11 <= 10, no, so we quit and continue to the next step. If it's counter++, then counter <= 10 will be evaluated, will return true (10 = 10), and only then the ++ will be evaluated. So now, counter = 11, we enter the do statement again, that prints 11, and then quits (11 is not <= 10).

anonymous · Answer

Try this...
int i=1;
1- cout<<++i; cout<<i;
2- cout<<i++; cout<<i;
You should understand from this the difference between prefix and postfix...