Question

prove the identity:
1 over sec x + tan x
=
1 - sin x over cos x

Answer 1

\[\left( 1 \over secx + tanx \right) = \left( 1-sinx \over \cos x \right)\]

Answer 2

LHS=cosx / (1+sinx)
LHS/RHS = (cos^2 x)/(1-sin^2 x)=cos^2 x / cos^2 x =1
so LHS=RHS

Answer 3

cosx / (1+sinx) ?

Answer 4

yeah that is LHS

Answer 5

multiply the numerator and denominator by cosx

Answer 6

oh yea

Answer 7

I don't get LHS/RHS? what's going on
hehe

Answer 8

divide LHS by RHS and found it is 1.
so we can say LHS=RHS

Answer 9

(1-sinx) times (1+sinx) is one?

Answer 10

(1-sinx) times (1+sinx) =