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Mathematics 19 Online
OpenStudy (anonymous):

prove that C(2m,0)^3-C(2m,1)^3+C(2m,2)^3-...+C(2m,2m)^3=((3m)!/(m!)^3)*(-1)^m

OpenStudy (anonymous):

\[C(n,k)= \left(\begin{matrix}n \\ k\end{matrix}\right)=n!/k!/(n-k)!\]

OpenStudy (anonymous):

Could you please expand the series series properly where exactly are the minus signs? THe first two terms are positive how did the third become negative

OpenStudy (anonymous):

the first item is positive, the second is negative and the third is positive again

OpenStudy (anonymous):

I am not sure for cubes but for squares just multiply two series and observe coeffecients.

OpenStudy (anonymous):

i have no idea, it is a really difficult problem

OpenStudy (anonymous):

This is actually dixon's identity i'm not sure how to prove it.

OpenStudy (anonymous):

oh..who is dixon? a mathematician?

OpenStudy (anonymous):

yeah dude obvi just google it you shld find it.

OpenStudy (anonymous):

yeah i find the identity, but not the proof

OpenStudy (anonymous):

If google does not have it what are the chances that a teenager does?? :D :D

OpenStudy (anonymous):

oh i find it http://math.ecnu.edu.cn/~jwguo/maths/dixon.pdf

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