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OpenStudy (anonymous):

Calculate the time in which a tuning fork of frequency 256 Kz. completes 32 vibrations?Answer needed urgently. Pl. help. Thanks !

OpenStudy (anonymous):

Well, frequency tells you how many times something happens in 1 second. so in 1 second you get 256 vibrations (I suppose Kz should be Hz, if it should be kHz then you have 256 000 vibrations in a sec). I think it is pretty easy now to calculate how much time it would take to get 32 vibrations.

OpenStudy (anonymous):

Thank you Gogind. but, can you give me the precise calculations, as it is important for my assignment and the resultant answer ? Would appreciate your help . Am repeating the question : Calculate the time in which a tuning fork of frequency 256 Kz. completes 32 vibrations?Answer needed urgently. Pl. help. Thanks ! S.Ramya

OpenStudy (anonymous):

I don't like to just spit out a solution for you, so I'll try to guide you to it. So you know how many vibrations you get in 1 second? Well yes, you know the frequency! So you know that in 1 second there are 256 vibrations (since it's a tuning fork It has to be 256 Hz, I don't know what Kz is, I suppose it's a typo). 256 Hertz, or Hz, means that the tuning fork vibrates 256 times in one sec. So, how long does it take to vibrate 32 times? It takes 256/32 times LESS then what it takes for 256 vibrations, so that's 1/(256/32) seconds, that is 0.125 seconds. Or you can say it takes 32/256 times MORE then what it takes for 256 vibrations, so that's (32/256)*1 seconds. Again you get 0.125 seconds. If you want I could write you a general formula of some sort, but I really don't think it is necessary.

OpenStudy (anonymous):

thank you very much goging!

OpenStudy (anonymous):

you've been very patient in explaining , I am much obliged and understood it clearly! Wishing you and other friends a very happy new year 2012 :)

OpenStudy (anonymous):

No problem, and I wish a happy new year to you too! :D

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