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OpenStudy (anonymous):

A particular transmitter of a radio statioin broadcasts at 422.5 m wavelength.Calculate the frequency at which the radio station broadcasts its programme.(Given, the speed of radiowave is 3 x 10 to the power of 3)m/s.Answer needed urgently. pl help. Thanks !S.Ramya S.

OpenStudy (anonymous):

to the power of 3? Could you check that?

OpenStudy (anonymous):

Hmm... I think we're off by a factor of a few here?

OpenStudy (anonymous):

You can calculate the frequency with the following formula: \[f=v/\lambda\] Where f - frequency, v - speed of the wave, lambda - wavelength

OpenStudy (anonymous):

we know that \[f=v/\lambda\] \[\lambda=422.5 m\] \[v=3*10^3\] so f would be \[7*10^3\]

OpenStudy (anonymous):

Shouldn't v be closer to 3 * 10^8?

OpenStudy (anonymous):

it should be!!!!

OpenStudy (anonymous):

Gogind : Deuter : Few Screws missing : It is 10 raised to the power of 3 !! Pl reply to the problem soon ! Repeating the question again for help : A particular transmitter of a radio statioin broadcasts at 422.5 m wavelength.Calculate the frequency at which the radio station broadcasts its programme.(Given, the speed of radiowave is 3 x 10 raised to the power of 3)m/s.Answer needed urgently. pl help. Thanks !S.Ramya S.

OpenStudy (anonymous):

Well, if it is to the power of 3 then just do what Deuter did. The reason we think this speed is strange is that the speed of the radio waves (electromagnetic waves) is 3 *10^8 m/s, that is, the speed of light (radiowaves travel at the speed of light). The given speed kinda looks like 3*10^8, except there's that 3. Anyways, do what Deuter did and ask your teacher to check it, I would say it is a typo.

OpenStudy (anonymous):

should I consider deuter's answer as final?

OpenStudy (anonymous):

Yes, if it really says 3*10^3, OR you can argue with the teacher that this makes no sense because the speed of the radio waves is 3*10^8 m/s. I would personally mention this to the teacher, but that's just me :D

OpenStudy (anonymous):

Yes, I will, for the time being take it as an answer but will definately ask the teacher about it! thank you once again for your guidance!

OpenStudy (anonymous):

correction:definitely

OpenStudy (anonymous):

Thanks to Deuter and Gogind and Few Screws Missing for all your help.S.Ramya

OpenStudy (anonymous):

I just now checked the question from the home assignment again.You are correct, It is 10 raised to the power of 8 and not 3.In fact, I just noted the error.Should I take Deuter's answer as it is now ?Pl guide.Ramya

OpenStudy (anonymous):

No. He used 3*10^3 m\s as velocity. You must use 3*10^8 m/s, just use the formula he wrote up there to calculate the frequency. I'm sure that if you try to calculate it you will not have problems.

OpenStudy (anonymous):

This formula... \[f = \frac{v}{\lambda}\]

OpenStudy (anonymous):

using the formula, I am getting 710059.17 as the answer but I am not sure. Is the answer correct?

OpenStudy (anonymous):

That's what I get too. So that's 710059.17 Hz or 710.059 kHz or 0.71 MHz

OpenStudy (anonymous):

I am relieve! Sorry to disturb you. Many thanks! Looking forward to your help in future too! S.Ramya

OpenStudy (anonymous):

correction:relieved

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