Solve x2 - 4x = 12 by completing the square, show work please!!
b is -4 half of b is -2 this answer, -2 times itself equals 4 and now we add 4 to both sides x^2 - 4x + 4 = 12 +4 Do you know the next step?
meverett, I understand what you're trying to do here, but your approach is useless without first explaining the general method of approach for completing the square.
You should either provide the complete solution, or if you're going to do it your way, provide the general method of approach
I motivate not hate ...
You assume something is "hate" ing on you.
Just transfer the 12 to the left and you can "break" it into (x+2)(x-6)=0 From that it follows, x=-2 and x=6
So in general, when solving quadratic equations using the complete the square method, you begin with a general form ax^2 + bx = c. Then you add (b/2)^2 to both sides, creating a perfect square on the left side. Once we have a perfect square on the left side, we put it in the form (x-b)^2 then solve for x algebraically. In this particular case, we have x^2 -4x = 12. So a = 1, b = -4 and c = 12 Since b = -4, (b/2)^2 = =(-4/2)^2 = (-2)^2 = 4 so b/2 = 4 Now we add 4 to both sides: x^2-4x +4 = 12 +4 Then put the left side in the completed square form: (x-2)^2 = 16 Now we can solve for x algebraically: x - 2 = +-sqrt{16} x = +4 + 2 x = -4 + 2 x = 6 x = -2
Thank you for the detailed explanation!!!
yw
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