If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalent to y from the second equation is substituted into the first equation. 2x – 5y = –3 6x – 3y = –3 Answer 2(2x + 1) – 5y = –3 2x – 5(2x + 1) = –3 2(–2x – 1) – 5y = –3 2x – 5(–2x – 1) = –3
Keke, do you have any thoughts on which one it could be?
I DONT KNOW I TRYED BREAKING IT DOWN BUT IT DIDNT WRK
B.!
Yep, Miss T has it, but she forgot to explain her steps so that Keke gets it too
2x - y = -4 2x = y - 4 2x + 4 = y
*5
Miss T, those are your steps? I thought you would have shown it this way: In general when using substitution for systems of equations, you solve for x or y in one equation, then substitute the expression for the appropriate variable into the other equation. In this particular situation, they want you to solve for y in the second equation, and replace its equivalent expression with y in the first equation. In the second equation, solving for y yields the following: 6x – 3y = –3 3(2x-y) = -3 2x - y = -1 2x + 1= y Therefore, y equals 2x + 1 In the first equation, we replace y with 2x+1 as follows: 2x – 5y = –3 2x-5(2x+1) = -3 And that is how we arrive at the correct solution, B
Sorry man I'm way to lazy for all that aha.
You didn't really have to do all of that. You could have just posted the correct solution steps.
But don't worry, I covered for you :D
No I expected the hero to swoop in and resolve it.!
Corney much.? Yeah I know again to lazy to come up with a decent joke.. Tisk Tisk Shake My Head.! -_-
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