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If you were to use the substitution method to solve the following system, choose the new system of equations that would result if x was isolated in the first equation. x + 6y + z = 2 x – 3y + 2z = –1 x + 5y + 3z = –4 Answer –9y + z = –3 –y + 2z = –6 3y + 3z = –3 11y + 4z = –6 y – 2z = 6 –8y – z = 3 11y + 4z = 6 2y + 5z = 3
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all you have to do is solve the first equation for x, so then x=-6y-z, then see which one of the solutions gives you the new system after you sub in (-6y-z) for the values of x in the other two equations. that will give you the answer.
Oh Keke, you can't just substitute x,y, and z this time :P
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