Question

the square root of X-6 - the square root of X = 3

Answer 1

im thinking we can probably square both sides of the equation

Answer 2

yep square both sides, you will have to FOIL left side

[sqrt(x-6) -sqrt(x)]^2 = 3^2

Answer 3

actually it may be easier to move the sqrt(x) to right side first before squaring both sides

sqrt(x-6)^2 = [3+sqrt(x)]^2

Answer 4

ok, so i got x-6= 9+x. is this when i foil?

Answer 5

No FOIL the [3+sqrt(x)]^2

it does NOT equal 9+x

(3+sqrt(x))(3+sqrt(x)) = 9+3sqrt(x) +3sqrt(x) +x

Answer 6

does this need up being a no solution problem?

Answer 7

anyway, the answer is No solution

sqrt(x-6) < sqrt(x)
sqrt(x-6) - sqrt(x) < 0

a number less than zero can never equal 3

Answer 8

Thank you for the help!