Question

prove:
(sin2x over 2-2cos^2x) = cotx

Answer 1

i think you mistyped something...

Answer 2

it should be sin2x over (2-2cos^2x) = cotx

Answer 3

\[\left( \sin2x \over 2-2\cos^2x \right) = cotx\]

Answer 4

first look at the numerator sin2x=2sinx cosx
then the deno 2-2cos^2 x = 2(1-cos^2 x)=2 sin^2 x= 2 sinx sinx
so LHS=nume/demo=2sinxcosx / 2sinxsinx = cosx/sinx=cotx