Question

6x^2-2x-1=0 how can i get this using a quadratic equation

Answer 1

Do you mean Quadratic formula?

If so,

let a = 6

b = -2

what is c?

Answer 2

a = 6
b = -2
c = -1

\[-b \pm \sqrt{b^2-4ac} \over 2a\]

Answer 3

Apply a quadratic of the form:
\[\Large a{x^2} + bx + c = 0\]
To the formula:\[\Large \frac{{ - b \pm \sqrt {{b^2} - 4ac} }}{{2a}}\]

Answer 4

finding the roots of the equation. it is the point where this graph cuts x axis

Answer 5

so would it be -1 +the square root of37over 12

Answer 6

thats the answer i came up with

Answer 7

\[\Large \begin{array}{l}
6{x^2} - 2x - 1 = 0\\
\frac{{2 \pm \sqrt {{2^2} - 4(6 \cdot - 1)} }}{{2 \cdot 6}}\\
= \frac{{2 \pm \sqrt {28} }}{{12}}\\
= \frac{{1 \pm \sqrt 7 }}{6}
\end{array}\]
Is what I came up with.