can a function be inverse of it self if yes than state its property?
yeah it can like f(x)=x
Is there a specific domain for these functions you are considering? If not, you can use:\[f:\mathbb{C}\longrightarrow \mathbb{C}\]\[f(z) = \bar{z}\] The complex conjugate function. This is a bijective function over the complex numbers, so it has an inverse. and its easy to see that:\[f(f(z)) = f(\bar{z}) = z\]so it is its own inverse.
In general if f(x)=f^-1(x) ,then f(f(x))=x
what i know is it should be symmetric about the line y=x
Or you can find a matrix A such that:\[A^2 = I\]Then create a linear transformation:\[T:\mathbb{R^n}\longrightarrow \mathbb{R^n}\]\[T(x) = Ax\]That would also do the job. It just depends on what your domain should be. Real Numbers? Vectors? complex numbers? Gotta be a little specific.
The inverse of a function is basically obtained by replacing x with y and y with x in other words taking image about the line y=x so on reflection if you get f(x) itself i.e, symmetric abt y=x then it is its own inverse.
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