Question

Add and simplify:

Answer 1

(x + 3)/(x^2 + 5x + 6)

Answer 2

\[\frac{1}{(x+3)(x+2)} +\frac{1(x+2)}{(x+3)\times(x+2)} \]
\[\frac{(x+2)}{(x+3)(x+2)} \]
\[\frac{1}{x+3} \]

Answer 3

Oh I forgot you could cancel it out......

Answer 4

but
\[x+2+1=x+3\]

Answer 5

so maybe you can cancel, but you cannot cancel
\[x+2\]

Answer 6

i got

Answer 7

woops.

Answer 8

@lisa, yes that is correct, but you have a common factor top and bottom of
\[x+3\] so you can cancel them.

Answer 9

leaving a "final answer" of
\[\frac{1}{x+2}\]

Answer 10

My bad, looked at it wrongly, sorry
\[\frac{1+x+2}{(x+3)(x+2)} \]
\[\frac{x+3}{(x+2)(x+3)} \]
\[\frac{1}{x+2} \]

Answer 11

oh that makes sense :)

Answer 12

i got x +3/(x+3)(x+2)..
then cancel the x+3
got 1/x+2
am i right?

Answer 13

yes :)

Answer 14

oke2 thanks..=)