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OpenStudy (anonymous):
Given the following function:
f(x) = { |3+x|/3+x if x < -3
x + K if -3 = x = 4 (K is a constant)
root(x) - 2 / x-4 if x > 4
Determine the lim x-> 4+ f(x)
I am not sure how to approach this problem.
14 years ago
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myininaya (myininaya):
\[\lim_{x \rightarrow 4^+}f(x)=\lim_{x \rightarrow 4^+}(\frac{\sqrt{x}-2}{x-4})\]
14 years ago
myininaya (myininaya):
you can factor the bottom
14 years ago
myininaya (myininaya):
\[x-4=(\sqrt{x}-2)(\sqrt{x}+2)\]
14 years ago
myininaya (myininaya):
any questions?
I looked at the part of function where x>4 because we wanted to look to the right of 4
14 years ago
OpenStudy (anonymous):
so we would get 1/4 as a result?
14 years ago
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myininaya (myininaya):
yes \[\lim_{x \rightarrow 4}\frac{\sqrt{x}-2}{(\sqrt{x}-2)(\sqrt{x}+2)}=\lim_{x \rightarrow 4} \frac{1}{ \sqrt{x}+2}\]
14 years ago
myininaya (myininaya):
1/(2+2) is 1/4
14 years ago
OpenStudy (anonymous):
wow! thanks so much, this makes way more sense now.
14 years ago
myininaya (myininaya):
great
14 years ago
OpenStudy (anonymous):
Great profile picture! @Zarkon
14 years ago
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OpenStudy (anonymous):
lim f(x)
14 years ago
OpenStudy (anonymous):
same answer as my prof wrote on the exam.. just didn't understand how he got it!
14 years ago
OpenStudy (zarkon):
@No-data ty
14 years ago
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