5 boys and 4 girls form a queue at the cinema. there are two brothers who want to stand together, the remaining 3 boys wish to stand together, and the 4 girls don't mind where they stand. In how many ways can the queue be formed?
if i'm not mistaken it should be 8P8 = 40320
incorrect
Is the answer 120?
the answer is 8640, but i have no idea how they got that!
not if the order amongst them can change
I think of it as 6 groups (4 girls, 2 brothers, 3 friends) for 6! orders however, the 2 brothers can be in 2 different orders 3 guys in 3! ways so 3! * 2 *6!
There are 2 (boy) groups and 4 individuals (girls), altogether 6 "units". There are 6!=720 ways to arrange 6 units. There are two ways to arrange the two brothers (AB or BA), and 3! ways for the three boys (3!) Altogether there are therefore 720*2*6=8620 ways,by the multiplication rule.
@phi Sorry, it's 6 of course.
6P6 * 3! * 2!
typo!
6! * 3! * 2! is correct.
yes, 8640.
oh i seee thank you!
how come the girls don't count ie 4!
The girls count, but they're part of the 6!. There's 6 different units of people 1 girl, 1 girl. 1 girl, 1 girl, 2 brothers, 3 friends.
oh i see
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