Question

The positive sum of two perfect squares is 32. What is the largest positive value of the sum of the two perfect square?

Answer 1

a^2 + b^2 = 32

?

Answer 2

sorry the question is should be "The positive difference of two perfect squares is 32. What is the largest positive value of the sum of the two perfect square?"

Answer 3

a = b = 4

Answer 4

sorry

Answer 5

oh, calculus?

Answer 6

no, i don't think so

Answer 7

\[a^2=b^2-32\]\[a, b \in \mathbb{Z}^+\]

Answer 8

\[7^2+9^2=130\]

Answer 9

(x^2-y^2)=(x+y)(x-y)=32
factors of 32: 1,2,4,8,16,32
For x & y to be integers, x+y & x-y must be both even, so
9^2-7^2=32, 9^2+7^2=130
6^2-2^2=32, but 6^2+2^2=30
So 9 & 7 are the numbers

Answer 10

thx

Answer 11

you're welcome! :)