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OpenStudy (anonymous):
4x^2+5x-6 I am having trouble solving this. If someone can show me the method to solve, it would be greatly appreciated!
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OpenStudy (anonymous):
Quadratic Formula
OpenStudy (anonymous):
Find the roots using the quadratic formula then insert the roots into
(x - root)(x - root)
to factorize
OpenStudy (anonymous):
thanks!
OpenStudy (anonymous):
4x^2+5x-6=0
x^2+(5/4)x-3/2=0
(x+5/8)^2=3/2+25/64=121/64
(x+5/8)=11/8 or -11/8
x=3/4 or -2
OpenStudy (across):
If you want to factor that, then you need to find a combination of numbers such that (ax+b)(cx+d)=4x^2+5x-6.
In this case, (4x-3)(x+2)=4x^2+5x-6.
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OpenStudy (anonymous):
\[4x^2+5x-6 = 0 \implies 8x + 5 = \pm \sqrt{121} \implies 8x = \pm11 -5 \implies x = -2 or 3/4\]
OpenStudy (anonymous):
x = -2,3/4
OpenStudy (anonymous):
\[(2+x) (-3+4 x) \] This means that either \(x=-2 \text{ or } x = \frac34 \)
OpenStudy (anonymous):
Thanks Everyone!!!
OpenStudy (across):
Haha, he's like: "Okay, okay, yes, I got it, guys! Could you leave now?" :P
You're welcome.
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OpenStudy (anonymous):
haha
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
@Across Lol
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