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another more question... ∫√(1- x²) -1 / √(1- x²) dx do I need to use substitution method? but then I got du = -2x dx but there's no such thing to solve it that way...
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no
then what should I use?
you can simplify it first
√(1- x²) -1 / √(1- x²) = √(1- x²) / √(1- x²) - 1 / √(1- x²)
1/sqrt(1-x^2) is simply gonna give you the sin inverse
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its x-(sin^{-1}x)
right +c of course
yes
simplify it
then the answer should be x - sin^(-1) x +c ? tq so much (:
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your welcome
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