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what number must be added to both the numerator and the denominator of the fraction 1/5 to get a fraction equaling 3/4
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11
how?
i got -11 but i dont understand why
\[\frac{1+x}{5+x}=\frac{3}{4}\]
then do you do 4(1+x) = 5 (3+x)
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?
correct nikkysterr, solve for x to get the answer :)
yeah but i get -11
4 + 4x = 15 + 5x
4x = 11 + 5x
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-1x = 11
x = -11?
That is because it's not 4(1+x) = 5 (3+x) it should be 4(1+x)= 3(5+x)
how about for 2/3 = 1/4
Now you should get 11 as the answer
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\[\frac{2+x}{3+x}=\frac{1}{4}\] Same method as the last one.
i get 4(2+x) = 1(3+x)
correct
but i get a -5/3
8+4x = 3 +1x
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yes that's the answer
4x = -5 +1x 3x = -5
its suppose to be positive
not always, it just says it needs to be added.
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