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Integral of (cos x/ sin x) from pi/4 to pi/2
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\[\int\limits_{\pi/4}^{\pi/2} (\cos x / \sin x)\]
What is the antiderivative of cotanget?
u - sub for this one. try \[u=\sin(x), du=-\cos(x)dx,-du=\cos(x)dx\] and you are just about done
Satellite73 is on a better track, follow that advice.
so the answer is -ln abs value of sin x
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and while you are at it, might as well make \[u(\frac{\pi}{4})=\frac{\sqrt{2}}{2}\] \[u(\frac{\pi}{2})=1\] so you don't have to change back when you integrate
get \[-\int_{\frac{\sqrt{2}}{2}}^1\frac{du}{u}\]
i thought that was that after u integrate du/u you get -ln sinx and then u evaluate that at both pi/4 - pi/2
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