The voltage in series is equal?
I mean is it: vt=v1=v2 or vt=v1+v2 ?
V_battery= V_resistor1 + V_resistor2 + ... + V_resistor3. This is one of the Kirchhoff's rules. It says that the algebraic sum of all the voltage drops in a given closed loop are equal to the algebraic sum of all the voltage sources.
... all the voltage sources in that closed loop.
Okay, so it's the second one right?
vt=v1+v2 ?
Yes it's the second one! Thank you verryyyy much :D
ok, np
Wait, can you take a look at this question: ( PLEASE ) A current of 0.5 A passes through a 10 ohm resistor R1 connected in series to a resistor R2. The voltage across the first resistor is 12V. What is the current in the first resistor? In the second resistor? How much is the voltage across the second resistor? How much is the voltage across the combination? The voltage across one resistor is 10 volts. The voltage across another resistor connected in series with the first is 12 volts. Find the potential difference across the combination
is R1 the first resistor? It doesn't make any sense...
This is what I got : The current in the first and the second resistor is 0.5 A ( because the current in series is the same for the whole circuit ) How do you find the voltage across the second resistor?
Yes R1 is the first resistor :)
Maybe if you draw a circuit with resistors.. it might help you figure it out :)
It says "The voltage across the first resistor is 12V" but it can't be. Voltage across a resistor is \[U_{R1} = I*R_1\] and since you know the current passing (0.5A) and the resistance (10ohm) the voltage across R_1 is 10*0.5= 5V
Yes, draw it and write the exact question from the textbook or where ever..
Why it can't be?
There is no drawing or anything...
Because the voltage drop over a resistor is defined by the Ohm's law:\[U=I*R\]
Here is the link if you want : ( question number 4 ) http://207.67.101.76/amsamman/AMS%20files/Sample%20Questions/Grade%208/Science/SQ%201112_19914-J_S%20_AMS_SQ.doc.pdf
What does U represent ?
ah sorry, In Croatia we use U for V so it's : \[V=I*R\]
Oh okay!
well, this question makes no sense, unless there was a change, because in the first sentence the voltage across R1 was 5 V (you get that using Ohm's law), and in the next sentence it is stated that the voltage across R1 is 12V.
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