If the integral of f(x-c)dx = 11 from 3 to 5, then the integral of f(x)dx from 3-c to 5-c is? I will write the equation w/ teh equation box
\[If \int\limits_{3}^{5} f(x-c) dx = 11\] then, \[\int\limits_{3-c}^{5-c} f(X) dx = ?\]
do a simple substitution
wat do u mean? wat shud i subsititute
u=x-c
so then du =1?
du=dx
then wat?
have you done u-substitution before?
yea but im still confused
u(x)=x-c \[\int\limits_{3}^{5}f(x-c)dx=\int\limits_{u(3)}^{u(5)}f(u)du=\cdots\]
is it 5-c - (3-c) = 2 - 2c
can u help me continue teh problem??
\[11=\int\limits_{3}^{5}f(x-c)dx=\int\limits_{u(3)}^{u(5)}f(u)du=\int\limits_{3-c}^{5-c}f(u)du\]
so the expression integral of f(x) dx from 3-c to 5 - c is 11?
yes
so there is no other number value for teh asnwer?
its just to prove that the 2 expressions are equal
they are equal
but i dont understand i thought wen u integrate an expression u are supposed to get smthg.
? ... you did ... it is 11
oh ok i guess i was jsut confused about wat teh question was aking...sorry XD
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