Question

if 8^x+8^x-1=10 then 2^2x

Answer 1

2.8^x=11 8^x=11/2take log x=(log11/2)/log 8 I think so but it looks like an improper method :)

Answer 2

or is the equation like \[8^{x}+8^{x-1}=10\]

Answer 3

if 8x+8x−1=10 then 2^2x...

Answer 4

What happened to the ^ sign in the question?

Answer 5

^ rank

Answer 6

Anyway if that is the question then 16x=11 x=11/16 2^2x=2^(11/8)

Answer 7

2 \[8^{x}+8^{x-1}=10 then 2^{2x}\]

Answer 8

ah ok so
\[8^{x}+8^{x}/8=10\]so 9.8^x=80 8^x=80/9 2^3x=80/9,
powering both sides bt 2/3 2^2x=(80/9)^2/3

Answer 9

ok..thanks :)

Answer 10

no problem :)