If g(x) = x^2 f(x), f(4) = 3 and f'(4) = -5, then g'(4) =?
differentaite both sides you g'(x)=2xf(x)+x^2f'(x) (by product rule) g'(4)=8f(x)+16f'(x)=24-80=-56
You know product rule right?
f'g + fg'
yeah so just apply it here g=x^2 and f is f only
wait y do u have to use g=x^2 and f =f ...didnt u answer te hquestion already and get -56
err yeah i was just explaining how i got the answer \m/
im still kinda confused
after u differentiated
If you want to get the answer just use product rule differentiate and get substitue the given values where exactly are u confused?
oh ok nvr mind....i was confused with how u got thsoe numbers, i forgot to substite
after i differentaited i put x=4 as you want g'(4) you know 2x=8,f(4)=3 and f'(4)=-5 i just substitued those in the equation i got to get the answer.
awesome...thanks! =) i get the problems after i see how to approach it
if i post anotehr problem on teh side can u help me
Yeah sure....
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