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How do you find the derivative of (cos x)^x?
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Do you know how to find the derivative of x^x ?
no :(
Write y = x^x, then ln y = x ln x We can differentiate the left hand side, LHS, using the chain rule: \[ y' \frac{1}{y} \] the the derivative of the RHS is \[ x.(1/x) + 1.\ln x = 1 + \ln x \] Hence \[ y' \frac{1}{y} = 1 + \ln x \] and \[ y' = y(1 + \ln x) = x^x(1 + \ln x) \] Now, imitate that procedure for your problem.
Logarithmic differentiation.
Ok. Thanks! :)
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