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can 27a^3(cubed) - 1 over 9a^2(squared) - 6a + 1 be reduced?
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yes. Factor both. The numerator uses the formula difference of cubes. The denominator is a perfect square. They both share a common factor of (3a-1)
I think it is (27a^3 - 1)/(9a^2 - 6a + 1) It can be reduced by factoring.
yes GT thats it. . . do u know the reduced form?
Factors of 27a^3 - 1 = (3a-1)(9a^2 + 3a +1) Factors of 9a^2 - 6a + 1 = (3a-1)(3a-1)
Dividing will give you.... (9a^2+3a+1)/(3a-1)
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ok good i did it right !! haha thank you
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