How many positive factors of the number 36,000,000 are not perfect squares?
\[6^{2}\times10^{6}\]
find the prime factorization first
\[(2*2*3*3)*(10*10*10*10*10*10)?\]? not sure
10 can also be broken down as 5 * 2
yeah, so \[2^{8}*3^{3}*5^{6}\]
In order for the number to be perfect factors, it is in the form: \[2^{2n} * 3^{2m} *5^{2p}\]
okay.
i don't fully understand... the form above?
for 2, n can be equal to 0, 1, 2, 3, 4; 5 choices for 3, m can be equal to 0, 1; 2 choices for 5, p can be equal to 0, 1, 2, 3; 4 choices
number of perfect squares is 5 * 2 * 4 = 40
do you know the answer?
9 * 4 * 7 = number of factors = 252
number of non-perfect squares' factors = 252 - 40 = 212
I had no clue that was how it was supposed to be done... i wish i was able to give more than a medal here, but thank you so much for your help :)
np
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