Question

Find the center of this ellipse: 4x^2 + 16y^2 +64x +64y + 256 =0

ANSWER PLEASE

Answer 1

4(x+8)^2+16(y+2)^2=-256+256+64
((x+8)/4)^2 + ((y+2)/2)^2 = 1
Can you figure out the centre?

Answer 2

No i can't and i reall would appreciate the answer..

Answer 3

An ellipse centred at origin has the equation
(x/a)^2 + (y/b)^2 = 1
If centred at (x0, y0), the equation becomes:
((x-x0)/a)^2 + ((y-y0)/b)^2 =1

By comparison with the equation
((x+8)/4)^2 + ((y+2)/2)^2 = 1
can you find x0 and y0?