how to find specific heat of a substance without Joules amount

Question

anonymous · Answer

What does the question ask? I think i need more information to help out here.

anonymous · Answer

"assume 35.8 grams of an unknown metal was heated to 100 degrees C. This heated metal was dropped into 100-ml of water at 24 degrees C. The water and metal ended up at 27 degrees C. Determine the identity of the metal by choosing from the table below (which consists of substances and their specific heat)"

anonymous · Answer

alright you are going to use the specific heat of water for this problem and set it up using the following formula

q=c*m* delta t

q= (4.184)(100)(3)
q=1255.2j 

now we know that if the water absorbs 1255.2j the metal gave up 1255.2j. so we will use the same fromula and solve for c

q=c*m* delta t
$$\frac{q}{(m)(\Delta T)}=C$$

$$\frac{-1255.2}{(35.8)(-73)}=C$$

C=.4802

see if there is a number like that in your table