can anyone help me get the inverse of this equation... y=2^0.25x-4 +4

Question

can anyone help me get the inverse of this equation...  y=2^0.25x-4   +4

jamesj · Answer

Like any such problem, you have y = f(x).  Solve the equation for x and find the function g such that
x = g(y).

That function g will be your inverse.

anonymous · Answer

do i do the log since 0.25x-4 is an exponent?

jamesj · Answer

Yes.  You're starting with
$$ y = 2^{(x/4) -4} +4 $$
hence
$$ 2^{(x/4) -4} = y -4 $$

Now take the log of both sides.

anonymous · Answer

i'm stuck at     logx-log4=0.25log2-log16

jamesj · Answer

Starting with my last equation, taking the natural log of both sides,
$$ ((x/4) - 4) \ln 2 = \ln (y-4) $$

Now, hopefully you can solve that equation for x?