without graphing, determine the equation whose graph intersects the graph of -6x + 3y = 11 exactly once. how do i get my answer?

Question

unklerhaukus · Answer

the only way to touch a parabola a a single point is to touch it at the vertex

anonymous · Answer

yes, but how do I figure this out without graphing? 
my choices are:
i) -6x + 3y = 13
ii) -24x + 12y = 44
iii) -4x + 3y = 11

anonymous · Answer

also iv) none, lol.

jagatuba · Answer

iii

jagatuba · Answer

y-intercept is 11/3

anonymous · Answer

how did you arrive there please.=

unklerhaukus · Answer

look at the right hand side of equations

unklerhaukus · Answer

the number is the same

anonymous · Answer

I must be looking at this wrong.. is  (-6x + 3y = 11) y=6/3+11 in y=mx+b format?

jagatuba · Answer

{y=2x+11/3, y=(4x)/3+11/3}

jagatuba · Answer

Y-intercept on both equations is 11/3 and the slope is different therefore the lines intersect at (0, 1/3)

jagatuba · Answer

(0, 11/3) sorry

anonymous · Answer

{y=2x+11/3, y=(4x)/3+11/3}  ; why is the mx = 2x and 4x???????

jagatuba · Answer

2x+11/3=(4x)/3+11/3