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Mathematics 19 Online
OpenStudy (austin1):

how do i find the altitude of a triangle

OpenStudy (anonymous):

I dont know perhaps look in the book?

OpenStudy (anonymous):

If the base length and area are given then you can find the altitude (1/2)*base*altitude=area There are many more ways

OpenStudy (chris):

Good point abdul. Depends on the type of triangle and information given - http://en.wikipedia.org/wiki/Altitude_(triangle)

OpenStudy (chris):

do you have a specific example?

OpenStudy (austin1):

|dw:1326213765773:dw|

OpenStudy (chris):

@Austin is the top angle 90 degrees?

OpenStudy (austin1):

yes

OpenStudy (austin1):

i need to find x

OpenStudy (anonymous):

Can you draw it more clearly?

OpenStudy (amistre64):

you have similar triangles then

OpenStudy (amistre64):

|dw:1326214098097:dw|

OpenStudy (amistre64):

without knowing another angle this might be difficult

OpenStudy (austin1):

|dw:1326214062730:dw|

OpenStudy (chris):

"Example 2" - same set up, right triangle, same information, uses this theorem: "If an altitude is drawn to the hypotenuse of a right triangle, then it is the geometric mean between the segments on the hypotenuse."

OpenStudy (austin1):

so how do i find what x is?

OpenStudy (chris):

Well, given this triangle, and the theorem I listed above

OpenStudy (chris):

We know that 1/x = x/3

OpenStudy (amistre64):

all these new fangled thrms :)

OpenStudy (chris):

so x^2 = 3, x = sqrt(3)

OpenStudy (chris):

lol I know =) not things you can just remember

OpenStudy (amistre64):

\[geometric\ mean:\ \sqrt[n]{a_1*a_2*a_3*...*a_n}\]

OpenStudy (austin1):

so x = sqrt of 3?

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