A toddler’s playground has two slides on either side. The slide on the left is situated at a 45° angle to the ground and is 68 centimeters away from the base of the playground. The slide on the right is positioned at a 30° angle to the ground and is 112 centimeters away from the playground’s base. What is the total length of both slides on this playground rounded to the nearest tenth of a centimeter?
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OpenStudy (swag):
OpenStudy (anonymous):
i wish i could copy the ansers and give um to u
OpenStudy (swag):
lmfaoo im guessing ur FLVS
OpenStudy (anonymous):
ya
OpenStudy (anonymous):
what test is that
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OpenStudy (swag):
GRRR I Need hoblos -.-
OpenStudy (swag):
04.04 Special Right Triangles
OpenStudy (anonymous):
give me a second
OpenStudy (swag):
ok
OpenStudy (anonymous):
im sorry
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OpenStudy (anonymous):
what ???? it vanished
OpenStudy (swag):
i found it already
OpenStudy (swag):
i need the 1 at the top
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
adjacent side / cosine of angle = length of hypotenuse.
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OpenStudy (hoblos):
first slide = 68sqrt2=96.1
second slide = 112/cos30 = 129.3
total length= 225.4
OpenStudy (anonymous):
Hence total length = (68/cos(45)) + (112/cos(30)) = 225.5
OpenStudy (hoblos):
lol i feel i've solved this same question here before
OpenStudy (anonymous):
Haha. De ja vu. And I swear the name SWAG looks familiar.