Please Answer this question if any1 can.. Is the radius of the hydrogen like species (he+,Li2+...) are same as hydrogen i.e 1 ??
No. The number of electrons in each may be the same, but the number of protons pulling on those electrons is different in each atom. The hydrogen atom has 1 proton pulling on 1 electron. The He+1 ion has 2 protons pulling on 1 electron. The Li+2 ion has 3 protons pulling on 1 electron. As the nucleus gets stronger, it draws that single electron closer and closer. The Li+2 will have the smallest radius of this set.
Thank you Then how would we calculate the radius of these orbits?? What should we take as the value of 'n' in the equaion r=0.529*n2 ??
You are missing part of the equation, it should be: \[r = 0.529*(n{^2}/Z)\] The value for n is determined by the number of the energy level, as numbered from closest (n = 1) to farthest (n = infinity). In each case here, n = 1, since a single electron will occupy the first energy level. The value for Z will be the atomic number of that particular atom or ion. For H, Z = 1; for He+1, Z = 2, and so on...
oh thnx i've got it nw...
Actually i was solvn a problm nd coudnt ans it... Q)ratio of the radii of the K shell n He+ nd Li2+ is: a) 3:2 b)2:3 c)1:3 d)3:1
solve for the radius twice, once for He+1, and once for Li+2. Then divide those two answers to get the ratio of the radii
Oh dude i knw tht buh i wanna knw how to solve fr the radius??
r in the equations above is the radius
okay.. buh i wanna knw wht value do we use for "n" in case of He+ nd Li+2?? this is wht i actually wanna knw..
see my original reply
So, eventually for He+ will have n=2 nd ni+2 will hav n=3
No. the "n" for each kind of ion is still 1, because the electron is occupying the lowest (n = 1) energy level, regardless of which ion you are looking at. The Z value for each ion will be different.
ohh... got it.. i'm sucha dumbo thnx anyay..
Join our real-time social learning platform and learn together with your friends!