if it rains tomorrow, the probability is 0.8 that john will practice the piano. if it does not rain tomorrow, there is only a .4 chance that john will practice. if there is a 60% that it will rain tomorrow, what is the probability that John will practice his piano lesson? i'm supposed to use a tree diagram to solve this

Question

anonymous · Answer

= (0.6 x 0.8) + (0.4 x 0.4)
= 0.48 + 0.16
= 0.64

anonymous · Answer

I've not done tree diagrams in a long time, but I think your first branches are whether or not it rains, and your second branches will be whether or not he practices piano in those situations.

amistre64 · Answer

rain:  .8  .4
no rain:  .2  .6

hmm

amistre64 · Answer

got my markov a bit off

amistre64 · Answer

rain   no rain
     practice:  .8      .4
no practice:  .2      .6

thats better, not that its anymore doable to me; but at least its better

anonymous · Answer

so how do i find the answer from the little chart u just made

amistre64 · Answer

still trying to work that out.  its been awhile and im nor really sure if this is even a markov chain application

anonymous · Answer

its a tree diagram

amistre64 · Answer

personally, I might plot both points to make a line and see where .6 falls into play; but thats prolly a bad idea

anonymous · Answer

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See if you can fill in the blanks yourself :D