the wight of a body varies inversly as the squareof its distance from the center of the earth. if the radius of the earth is approximatly 6378km, how much would a 100 kg man weigh 2000km above the surface of the earth?

Question

anonymous · Answer

So let the weight be a function of distance.
W=k/x^2. first when x=radius of earth=6378 km W=100kg so find the constant of proportionality k.
After finding k put x=2000 and find W.

anonymous · Answer

i dont understand

pokemon23 · Answer

hero btw i got the glasses?

hero · Answer

Thank goodness

pokemon23 · Answer

I thought you were going to say that

anonymous · Answer

Ok look W is proportional to 1/x^2. So then w=k/x^2.I just put a constant of proportionality k.Understood?

anonymous · Answer

anyone understands what he meant to explain me in a simple way

anonymous · Answer

$$w=k/d ^{2}$$

given radius=6378; w=100kg$$100=k/6378^{2}$$$$100=k/40678884$$$$k=100(40678884)$$$$k=4067888400$$then proceed on finding W.   since we have the value of k

d= 6378(from the center to the surface)   +  2000(above the surface)
$$w=4067888400/8378$$$$w=4855440917 kg.$$

anonymous · Answer

is that what you ment before shankvee\

anonymous · Answer

oh i forgot square the denominator first before dividing it. .

anonymous · Answer

that's 57.95 kg

anonymous · Answer

what did you do to get 57.95

anonymous · Answer

square 6378, then divide to the numerator. .

anonymous · Answer

you lost me now can you start from where you forgot to do that

anonymous · Answer

please can you help me Jerwyn gayo