Question

PLEASE HELP
expand the logarithmic expression
(will input expression w/ the equation creator)

Answer 1

\[\log _{6} c/4\]

Answer 2

Do you want the series expansion of log or do you want to write it as \[\log_{6} c- \log_{6} 4\] (log a/b)=log a- log b

Answer 3

2nd, to give me a more simple answer, not series expansion

Answer 4

Mth3v4 I cant see what you wrote can post a link please is says canot conect to web

Answer 5

So just use log(a/b)=log a- log b the answer i have already mentioned.

Answer 6

so what the expanded form be log base 6 c over log base 6 4?

Answer 7

What you have posted is log base 6 c over 4 NOT
log base 6 c over log base 6 4.

Answer 8

so i have it flipped around, the denominator i have is the numerator and vise-versa?

Answer 9

What on earth are you saying? The answer is just \[\log_{6}c-\log_{6}4 \]

Answer 10

haha sorry, i just dont see that in mmy multiple choice answers, what is it in series?

Answer 11

im sorry, thanks for helping me

Answer 12

No problem :)

Answer 13

nvm i got it, thanks!!