find out the possible blood groups and genotypes of the children of following parents:(a)Mr.x=O group Mrs.x=B group (b)Mr.y=A Mrs.y=AB (c)Mr.z=A Mrs.z=A
a. You're told that the male is O, which means he doesn't have either the A or B allele on either of two homologous chromosomes. His genotype is OO. The female is B, which means her genotype is either BB (homozygous) or BO (heterozygous) for the trait. Because you have these two different possible genotypes for Mom, you'll have to set up two crosses. 1. OO Dad x BB Mom ---> All offspring will have BO genotypes and exhibit a pure B phenotype. 2. OO Dad X BO Mom ---> 1/2 offspring will be BO and will exhibit a pure B phenotype, 1/2 offspring will be OO will exhibit an O phenotype. Is that enough help to get you going on the rest of the problem?
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