Question

what does this mean? scanf("%d",&n);

Answer 1

This means that the program will wait for input and take a (d)ecimal and place it in the address of the n variable
.

Answer 2

so can u rephrase it in "cin" ?? because scanf means cin right??

Answer 3

It means it will prompt the user to input a integer number and store its value in 'n'. %d signifies that the data type of input should be an integer. & signifies that it is stored in a particular address.

Answer 4

they are similar. scanf is for c and cin is a c++ construct.

Answer 5

yep. but i want it to be just clear. ahmm by just showing "cin and cout". so can u rephrase that into cin ??

Answer 6

im using c++ actually not c. so im really confuse

Answer 7

#include <iostream>
using namespace std;
int main()
{
int n;
cin >> n;
cout << n << endl;
return 0;
}

Answer 8

The scanf requires the type to be specified, the cin will display based on the type of variable.

Answer 9

can u show me a code. printing a pyramid ? for example, i type 5. this would be the output:

*
**
***
****
*****

Answer 10

Pyramid example:
#include <iostream>
using namespace std;
int main()
{
int count;
cin >> count;
for(int i = 1; i <= count ; i++)
{
for (int j = 1; j <= i; j++)
{
cout << "*" ;
}
cout << endl;

}
return 0;
}

Answer 11

if you use c++ use cin

Answer 12

Scanf is a C standard-library function which reads data from the stdin channel, decodes it according to the format string (argument 1), and stores it in the variable that argument two points to. Lots more info at http://dinkum.com/manuals/?manual=compleat&page=lib_scan.html#Scan%20Functions.