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find the following integral...
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\[\int\limits_{}^{}(8x-3\div12x^8) dx\]
\[\int\limits{\frac{8x-3}{12x^8}dx}?\]
yes but i made a mistake 12x^6
Split up the fraction and it will be very easy.
\[\int\limits{\frac{8x}{12x^6}dx}- \int\limits{\frac{3}{12x^6}dx}\]
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ok, so what would i do next? sorry, I'm new.
i think you can then integrate by writing the two parts as negative exponent
= INT (2/3) x ^-5dx - INT(1/4) x^-6 dx
simplify it further
yeah, i got to that but how would you simplify further than that?
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lalaly should have finished posting her steps
You have to move the numerical fractions outside the integral because they are constants
|dw:1326315737577:dw|
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