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A clock with a radius of 15 cm has an 11 minute hand on a 7cm hour hand. How far apart are the tips of the hands at 3:30. Hint: you use the sine or cosine law to solve this
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It would appear that the angle included between the hour and the minute hand at 3:30 would be 75 degrees 2.5/12 X (360) degrees = 75 degrees. You now have the included angle of 75 degrees, with one side being 11 the other being 7, you can find the third side which is the desired answer
\[c ^{2}=7^{2}+11^{2}-2(7)(11)\cos 75^{0}\]
\[c ^{2}=49+121-(2)(7)(11)(.2588)\] \[c ^{2}=170-39.8552\] \[c ^{2}=130.1448\] \[c=11.408 cm\]
Check for errors lol
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