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How many years will it take for a $50 investment to grow to $100 if it is compounded continuously at a rate of 5%? Given formula is: A(t)=P*e^rt Where P is initial investment, r is rate, t is time.
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100 = 50*e^0.05t 100/50 = e^0.05t 2= e^0.05t ln 2 = 0.05t t = (ln2)/0.05 = 13.86 years nearly. so 14 years i guess
A(t) = 50* e^(0.05*t) - like rkothaka said
btw the $50 and the $100 have nothing to do with it. this is the "doubling time" so no matter what you start with it will double in \[\frac{\ln(2)}{.05}\] years
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