Find the equation of the quadratic function with zeros at -1, and 1 and vertex at (0, -6).

Find the equation of the quadratic function with zeros 10 and 14 and vertex at (12, -8).

Question

Find the equation of the quadratic function with zeros at -1, and 1 and vertex at (0, -6).

Find the equation of the quadratic function with zeros 10 and 14 and vertex at (12, -8).

amistre64 · Answer

first you construct it for the zeros: we know the xs so find the "a" "b" to fit

(-1+a)(1+b) = 0

a = 1 and b = -1

(x+1)(x-1) = 0

now, when x=0, what do we have to multiply it by to get it to equal -6?

amistre64 · Answer

n(0+1)(0-1) = -6

n(1)(-1) = -6

-n = -6

n=6

6(x-1)(x+1)=0 should suffice

amistre64 · Answer

there might be an easier way to do that, but thats just what came first to me head :)

anonymous · Answer

and what about the second one?

amistre64 · Answer

y = a(x-h)^2 + k

where vertex = (h,k)

amistre64 · Answer

the second one is the same process; just different numbers

anonymous · Answer

y = 2x2 + 48x + 280
 		
y = -2x2 - 48x + 280
 		
y = -2x2 + 48x - 280
 		
y = 2x2 - 48x + 280

these are my choices

amistre64 · Answer

since we know 12,-8

y = a(x-h)^2 + k

y = a(x-12)^2 -8

is one setup

amistre64 · Answer

i like the other method better tho

anonymous · Answer

http://i729.photobucket.com/albums/ww292/akatushi101/A2_Image_SemesterAFinal_278.gif Given the following triangle, solve for angle C. is it 56 degrees?